What values of a and b make the equation true? the square root of 648 = square root of 2^a * 3^bA. a=3, b=2B. a=2, b=3C. a=3, b=4D. a=4, b=3
Accepted Solution
A:
Answer: OPTION CStep-by-step explanation: To solve the exercise you must descompose the number 648 into its prime factors, as you can see below: [tex]648=2*2*2*3*3*3*3[/tex] You can rewrite the above as following: [tex]648=2^3*3^4[/tex] Then: [tex]\sqrt{648}=\sqrt{2^3*3^4}[/tex] Therefore, as you can see, the value of a and b are the following: [tex]a=3,b=4[/tex]