what is a formula for the nth term of a given sequence-12,-16,-20...an = -12(-4)^n a^n = -12 - 4 (n+1)an = -8 - 4nan = -12(-4)^n-1
Accepted Solution
A:
Answer:[tex]a_n=-12-4(n-1)[/tex]Step-by-step explanation:The given sequence is -12,-16,-20...The first term of this sequence is [tex]a_1=-12[/tex].The common difference is [tex]d=-16--12[/tex][tex]d=-16+12=-4[/tex]The nth term of this arithmetic sequence is;[tex]a_n=a_1+d(n-1)[/tex]We substitute the values for the first term and the common difference to obtain;[tex]a_n=-12-4(n-1)[/tex]