Find the value of k so that the graphs of 8y=kx-4 and 6x+24y=12 are perpendicular.
Accepted Solution
A:
kx= 4 // Solve equation [1] for the variable x [1] 6x = 24y - 30
[1] x = 4y - 5// Plug this in for variable x in equation [2] [2] -12•(4y-5) - 24y = -36
[2] - 72y = -96
// Solve equation [2] for the variable y
[2] 72y = 96
[2] y = 4/3 // By now we know this much : x = 4y-5
y = 4/3// Use the y value to solve for x x = 4(4/3)-5 = 1/3 Solution : {x,y} = {1/3,4/3}